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Get access to the detailed solutions to the previous years questions asked in IIFT exam
7! can be broken into prime factors.
7! = 1*2*3*4*5*6*7 = 24 ∗ 32 ∗ 5 ∗ 7
Hence, the smallest perfect square which is divisible by 7! will 24 ∗ 32 ∗ 5 ∗ 7 = 5040*5*7 = 176400