- Study Anytime, Anywhere through Our Mobile App & Web Portal
- 1000+ Video Lectures by CAT/XAT Topper Faculties
- 400+ Hours content of CAT Preparation Videos
- 9000+ Questions in Online CAT Coaching Course
- 200+ Topic Based Tests (50+ Basic, 50+ Moderate & 50+ Advanced Level)
- 20+ CAT Mocks (Pro CATs – Best Online Tests Series for CAT)
- 10+ Mock OMETs (Online Test Series for SNAP, NMAT, IIFT, XAT, TISS, CMAT)
- Online Doubt Solving on One – to – One basis
- GD-PI-WAT Online Preparation Material
Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
Total number of students is 250, and we are told that, The percentage of girls was at least 44% and at most 60%.
So the number of girls range from, 0.44 (250) ≤ Girls ≤ 0.6 (250)
110 ≤ Girls ≤ 150
Statement 1:
If 50% of the boys and 80% of the girls opted for swimming, that means if the total number of Boys is B, Girls is G where B + G = 250
Swimming is: 0.5B + 0.8G
Statement 2:
If 70% of the boys and 60% of the girls opted for running, that means
Running is 0.7B + 0.6G
Total number of enrolments for swimming and running together will be
(0.7B + 0.6G) + (0.5B + 0.8G) = 1.2B + 1.4G
Using the overlapping principle, where I represents people who have enrolled only for one activity and II represents number of people who have enrolled for two activities.
We know that, I + II = 250 = B + G
I + 2II = 1.2B + 1.4G
Subtracting the two equations,
II = 0.2B + 0.4G
II = 0.2 (B + 2G)
Using B + G = 250
II = 0.2 (250 G)
G can at-most be 150 and at least 110.
So maximum value of II will be 0.2 (250 + 150) = 80
Minimum value of II will be 0.2 (250 + 110) = 72