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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
1800 = 23 × 32 × 52
= 2 × 3x (22 × 31 × 52)
= 6x (22 × 31 × 52)
Number of factors of 1800 which are also multiple of 6 = Number of factors of the highlighted part of the number = (2 + 1)(1 + 1)(2 + 1)
= 3 × 2 × 3 = 18