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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
We can choose 4 object in different ways
(i) 0 indistinguishable 4 distinct
= qc4
(ii) 1 indistinguishable & 3 distinct
1 × qc3
(iii) 2 indistinguishable & 2 distinct
1 × qc2
(iv) 3 indistinguishable & 1 distinct
1 – qc1
(v) 4 indistinguishable & 0 distinct
1 × qc0
Total ways of choosing 4 objects = qc0 + qc1 + qc2 qc3 + qc4
= 1 + q + 36 + 84 +126
= 256