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Get access to the detailed solutions to the previous year's questions asked in XAT exam.
Sum of 3rd row = sum of 2nd column
=> 2x+4y = y+2z-1
=> 2x+3y-2z= -1 ------- (A)
Sum of diagonals are also equal
=> 3x+4y+z-1 = y+z+2x+y+z
=> x+2y-z=1 -----(B)
Solving A and B we get y= 3
Putting it in A, we get x-z = -5 ----- (C)
Sum of 1st row = sum of 2nd column
5x+5y+z = 3x+4y+2z
=> 2x +y - z =0
Since y=3, 2x-z = -3 ------ (D)
Solving C and D we get x=2 and z=7
Hence N = 36