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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
We are given that on day 3, a total of 100 ratings came in
The modes were 4 and 5, meaning that an equal number of 4 and 5 ratings came in; let it be 10b (since we are given that all ratings were non-zero multiples of 10)
Let's take the number of 1 and 2 ratings as 10a each, giving the number of 3 ratings as 20a
Adding all of these up: 10a + 10a + 20a + 10b + 10b = 100
40a + 20b = 100
2a + b = 5
The only integer combination for a and b, without them being zero, is a being 1 and b being 3 or a = 2 and b = 1
But taking b as 1 would make 3 as the mode rating, so we can not consider the latter case.
We are giving 10 - 1 ratings, 10 - 2 ratings, 20 - 3 ratings, 30 - 4 ratings, and 30 - 5 ratings.
The average would be