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Get access to the detailed solutions to the previous years questions asked in IIFT exam
It's given that 120 students study Spanish : A + B = 120 ...(1)
Also 100 students study Mandarin : B + C = 100 ...(2)
At least 80 students will not opt for any of these two languages i.e.
Spanish + Mandarin (290-80)
Spanish + Mandarin 210
A + B + C 210
Case 2: When B is minimum and A is maximum.
Solving for boundary condition A + B + C = 210 ...(3)
Solving equations (1)+(2)-(3)
B = 10
i.e. A = 120 - B = 120 - 10 =110 {Maximum possible value of A}
Case 2: When B is maximum and A is minimum.
Since B+C = 100 so, Maximum value B can attain is 100. Hence, the minimum value of A = 120 - B = 120 - 100 = 20 {Minimum possible Value A )