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Get access to the detailed solutions to the previous years questions asked in CMAT exam.
Let say f(x) = x3 + 2x2 + bx + 68 and given (x + 4) is a factor of f(x).
=> f(x) = (x + 4) × k…………. (1)
Where ‘k’ is the quotient when f(x) is divided by (x + 4).
Substituting ‘x = -4’ in the equation (1), we get f(-4) = 0
=> -43 + 2(- 4)2 + b (-4) + 68 = 0
=> -64 + 32 – 4b + 68 = 0
=> 4b = 36
=> b = 9.