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Get access to the detailed solutions to the previous years questions asked in CMAT exam.
There are 2 physics teacher. They can stand in a row in ways P(2, 2) = 2! = 2 × 1 = 2 ways
Similarly, the two Chemistry and Mathematics teacher can stand in 2 ways each.
These three sets can be arranged in themselves in ways 3! = 3 × 2 × 1 = 6 ways
=> Required number of ways = 2 × 2 × 2 × 6 = 48