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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
Ar ?AOB : Ar ?DOC
Property of quadrilateral is that the product of opposite triangles = product of other 2 opposite triangle pair i.e.
Ar ?AOB × Ar ?DOC = Ar ?AOD × Ar ?BOC
4K × 9K = xy
xy = 36K2
Total area of quadrilateral = 4K + 9K + x + y
For x + y to be minimum where product of xy is given for that we use
AM ≥ GM
For AM to be minimum
AM = GM
(x + y)/2 = √(36K2)
(x + y)/2 = 6 K
x + y = 12 K
By putting x+y in area of quadrilateral
= 4K + 9K + 12K
Area = 25 K
For minimum area K = 1
Area = 25 Sq. units