IPMAT 2019 - Quantitative Aptitude Question 20
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IPMAT 2019 - Quantitative Aptitude
Let P = set of multiples of 4
Q = set of multiples of 6
R = set of odd multiples of 9.
∴ P = {4, 8, 12, ...... 996} = 249 elements
Q = {6, 12, 18, ..........996} = 166 elements
R = {9, 27, 45, .............999} = 56 elements
Now, this question can be easily solved through a Venn diagram
P ∩ Q is set of all the multiples of 12 ( 4 & 6) i.e.
{12, 24, 36..........996} = 83 elements
Also P ∩ R, Q ∩ R, P ∩ Q ∩ R will be 0 as P and Q consists of only even numbers while R consists of only odd.
∴ Total numbers = 166 + 83 + 83 + 56 = 388