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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
In ?ABD, ∠ABD = ∠ACD = x (let′s say) (? AB = AC)
Now, take ∠CDE = y
∠AED = x + y (Using exterior angle property)
∴ ∠ADE = x + y (ADE is an isosceles ?, AD = AE)
∴ ∠DAE = 180° − (2x + 2y)
Using angle sum property, in ?ABC
A + ∠B + ∠C =
x + (30° + 180 − 2x − 2y) + x = 180°
2y = 30°
y = ∠CDE = 15°