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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
Single digit nos. → 9
Two digit such no. = 9 × 9 = 81
Three digit such no. = 9 × 9 × 8 = 648
Total no. of natural nos. less than 1000 with no digit repeated = 9 + 81 + 648 = 738