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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
“At Least one boy sitting between any two girls” can be inferred as “No two girls should sit together”.
First, arrange 5 boys around a circular table. This can be done in (5 – 1)! = 4!
Now, there are 5 gaps available where we can make 3 girls sit in 5P3 ways.
In this arrangement, no two girls will be sitting together.
Total ways = 4! × 5P3
Probability