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Get access to the detailed solutions to the previous years questions asked in IIFT exam
(i) S -> Purple
P,R,N -> Purple (or) P,R,N -> Blue
(ii) P -> Purple
S -> Blue N,R -> Purple (or) S -> Purple N,R -> Blue
(iii) N -> Blue
P,R,S -> Purple (or) P,R,S -> Blue
(iv) R -> Blue
S,P -> Blue N -> Purple (or) S,P -> Purple N -> Blue
Let us consider N is in blue, then P, R, and S should be either in blue or purple.
If N is in blue and (P,R,S) is in blue, then this doesn't satisfy the condition in statement 4. If N is in blue and (P,R,S) is in purple, then this
violates statement 2. Therefore, N cannot be in blue and stays in Purple room.
Let us consider S is in purple, then P, R, and N should in purple as N cannot be in blue.
If S is in purple and (P,R,N) is in purple, then this violates statement 2. Therefore, S cannot be in purple and stays in Blue room.
Possible arrangements are:
1. P - purple, S - blue, (N,R) - purple
2. R - blue, (S,P) - blue, N - purple
Rooms of N and S are unchanged in all the cases.
The answer is option C.