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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
Let, n(FW) – Number of people who owns 4-wheelers, n(TW) – Number of people who owns 2-wheelers, n(FW ∪ TW) – Number of people who owns at least one of the vehicles, and n(FW ∩ TW) – Number of people who owns both type of vehicles
Now, the number of people who owns at least one of the vehicles = Total people surveyed – Number of people who owns none
(FW ∪ TW) = 500 – 100 = 400
Using the standard formula in set theory,
n(FW ∪ TW) = n(FW) + n(TW) – n(FW ∩ TW)
400 = 250 + 100 – n(FW ∩ TW)
So, the number of people who owned both are (FW ∩ TW) = 50