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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
Option (a) 3200 = (32)100 = 9100
Option (c) 4100
Option (d) 2300 = (23)100 = 8100
Clearly, among the option (a), (c) and (d) the exponent is same.
So, the option with largest base will be largest.
So, among these three options, option (a) is largest.
Now option (b) is 2100 + 3100 < 3100 + 3100
Or, 2100 + 3100 < 2x 3100
And, 2x3100 is certainly less than 3200 i.e. option (a)
That means, option (b) is less than option (a).
∴ Option (a) is the highest.