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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
Given x1 + x2 + x3 + x4 = 50 …(i)
And x1 ≥ 1 or x1 − 1 ≥ 0 |x2 ≥ 2 or x2 − 2 ≥ 0 |x3 ≥ 0|x4 ≥ 0
Let x1 − 1 = a |x2 − 2 = b |x3 = c |x4 = d
So, now we have a, b, c, d ≥ 0
Equation (i) can be written as (a + 1) + (b + 2) + c + d = 50
Or, a + b + c + d = 47
We have to find non-negative integer solution of above equation.
It can be find be find out using the formula n+r−1Cr−1 where, n = 47 & r = 4
∴ Total number of solutions = 47+4−1C4−1 = 50C3
= 19600