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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
Let the number of apples and oranges be x and y.
Then the number of bananas = x + 10
Total number of fruits = 2x + y + 10
As per the question, x + (x +10) = 11k (where k is a multiple of 11)
2x + 10 = 11k
k = (2x + 10)/11 ...….(i)
Also, total fruits sold by the seller can be expressed in two ways.
Equating both the expressions, we get
14x + 12x + 120 + 10y = 22x + 11y + 110
4x + 10 = y ...…(ii)
Now, it is given that the fruit seller sold 70% of apples i.e. 7x/10
In order to keep this number an integer, x must be a multiple of 10.
The smallest value of x in eqn.(i), for which k = (2x+10)/11 will be an integer is 50, a multiple of 10.
Substituting, x = 50 in eqn.(ii), we get
y = 4(50) + 10 = 210 oranges.