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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
x2 − 10|x| − 56 = 0
We know, if x ≥ 0, then |x| = + x
x2 − 10x − 56 = 0
(x − 14)(x + 4) = 0
x = 14 or − 4 (only one root, + 14 is valid)
Also, if x < 0, then |x| = − x
x2 − 10(− x) − 56 = 0
x2 + 10x − 56 = 0
(x + 14)(x − 4) = 0
x = − 14 or + 4 (only one root, − 14 is valid)
So, only 2 real solutions.