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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
Let us assign the amount of work done by Renu in one hour is R
And the amount of work done by Seema in one hour is S
We are told that a certain task with different time durations for Seema and Renu
Renu = 15 days with 4 hours each day, that is total work done by Renu is 15 × 4 × R = 60R
Similarly for Seema, 8 days and 5 hours each day, total work done by Seema is 40S
We know that 60R = 40S or S = 1.5R
For this task, let us assume that the amount of days that Seema decides to work is X and the hours per day that Renu decides to work is Y
We are then told that, Seema works for 2Y hours per day and Renu works for 2X days,
Work done by them will be 2XYR and 2XYS
We are told that Y = 2, Making this 4XR and 4XS
S = 1.5R
Total work will be, 4XR + 6XR – 60R
We get the value of X = 6
X is the number of days Seema will work, which is 6.