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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
Let the number of oranges, apples and bananas be 3x, 6x and 7x.
As the number of oranges is multiple of both 5 & 6 i.e. 30 (LCM of 5 & 6 is 30).
Their minimum number could be 30 only.
∴ 3x = 30
Hence x = 10 (minimum)
For minimum number of total fruits = 3x + 6x + 7x = 16x
16 × 10 = 160