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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
1 digit numbers = 2 (1 or 3)
2 digit numbers = 2 × 2
3 digit numbers = 2 × 2 × 2
6 digit numbers = 2 × 2 × 2 × 2 × 2 × 2
Now for 7 digit numbers = 1222222
We cannot place ‘3’ on the 1st position
∴ Total = 2 + 21 + 23+ .....26 + 26
= 190