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Get access to the detailed solutions to the previous year's questions asked in XAT exam.
Let the number of girls in the school be G.
=> Number of boys = G+30.
Some girls joined the class and the number of boys and girls became 3:5.
Let the number of girls who joined the class be 'X'.
It has been given that (G+30)/(G+X) = 3/5
5G + 150 = 3G + 3X
2G + 150 = 3X
=> X = (2G/3) + 50.
2G has to be divisible by 3.
Therefore, the least value that G can take is 3.
When G = 3, X = 2 + 50
X = 52.
The least number of girls who could have joined is 52.
Therefore, option C is the right answer.