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Get access to the detailed solutions to the previous year's questions asked in XAT exam.
To maximize Z, B has to be minimized and A,C,D are to be maximised.
The value of B can be 0 or 1.
Case 1:
B=0 => A=1=> C=8 and D=12.
Z= 15+8+6=29.
Case 2:
B=1 => A=0=> C=12 and D=15.
Z=-3+12+7.5=16.5.
.'. D=12 is correct answer.