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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
To solve this question, we need to immediately recognise the fact that, 32768 = 85
Substituting this in the above given equation,
Since the bases are equal, we can equate the powers on either side of the equation,
3k2 + 5k = 3k + 15
3k2 + 2k – 15 = 0
Here in the given quadratic equation, the Discriminant is greater than 0, 22 – (4) (3) (– 15) > 0
That means both the roots are real, hence we can simply take the sum of the roots of the quadratic equation in k,
Which in a standard quadratic equation of the form ax2 + bx + c is – b/a
Here, the sum of the real values of k is – 2/3