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Get access to the detailed solutions to the previous years questions asked in IIM IPMAT exam
Since we can only walk along the side of lakes, that drastically reduces the paths we can take.
The diagram below shows the path with the maximum distance travelled.
The path is CD-DE-EF-FK-KL-LM-MN-NK-KJ-JG-GF-FC
(the reverse of this path is also valid)
We can either manually add the lengths or use shorter methods to note that in the path we travel walkways of length 400 m 4 times (DE, LM, KN, EF), walkways of length 300m 6 times (CD, EF, KL, MN, KJ, GF) and walkways of length 200 m 2 times (FK, JG)
Giving the total length to be 1600 + 1800 + 400 = 3800