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Get access to the detailed solutions to the previous years questions asked in CMAT exam.
Since balls of same color should come together, let us consider 3 red balls as one unit and 2 blue balls as one unit and 4 yellow balls as another unit.
So, we have a total of 3 different units which can be arranged in '3!' ways.
These 3 red balls can internally be arranged in '3!' ways.
Similarly the blue balls and yellow balls can be arranged internally in '2!' and '4!' ways respectively.
So, total number ways = 3! × 3! × 2! × 4!
= 6 × 6 × 2 × 24 =1728 ways