- Study Anytime, Anywhere through Our Mobile App & Web Portal
- 1000+ Video Lectures by CAT/XAT Topper Faculties
- 400+ Hours content of CAT Preparation Videos
- 9000+ Questions in Online CAT Coaching Course
- 200+ Topic Based Tests (50+ Basic, 50+ Moderate & 50+ Advanced Level)
- 20+ CAT Mocks (Pro CATs – Best Online Tests Series for CAT)
- 10+ Mock OMETs (Online Test Series for SNAP, NMAT, IIFT, XAT, TISS, CMAT)
- Online Doubt Solving on One – to – One basis
- GD-PI-WAT Online Preparation Material
Get access to the detailed solutions to the previous year's questions asked in XAT exam.
Let's five small drums have a capacity of 1 unit capacity each and one bigger drum has that of 2 units capacity. We need to consider two
cases here. One with minimum volume and the other with maximum volume.
Case 1: Minimum value is possible if the bigger drum is half filled. So, total volume of water = 1 + 2 * (1/2) + 2 * (2/3) + 1 = 26/6 ~ 4.3
Case 2: Maximum value is possible if the bigger drum is completely full. So, total volume of water = 2 + 3 * (1/2) + 2 * (2/3) = 29/6 = 4.833
In any case volume of water is more than 4 units and less than 5 units. Hence, exactly 5 smaller drums are adequate to store the water.