IPMAT 2020 - Quantitative Aptitude Question 9

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IPMAT 2020 - Quantitative Aptitude

d = 3000m
Length of track = 300m
No. of Rounds = 3000/300 = 10 rounds
Ratio of speed = 3 : 2
When they will meet for the first time then the faster person have covered exactly 1 round extra then the slower person. So if they meet after faster runner have covered n rounds.
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Time taken would be same for faster runner completely & slower runner completing (n – 1) rounds.
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They will meet after every 3 rounds so number of times the winner passes other is = 10/3
= 3 times

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